11 KiB
| id | title | section | difficulty | estimated_time | prerequisites | objectives | tags |
|---|---|---|---|---|---|---|---|
| phys-04 | Empirical ε Values and Calibration | Spark Growth Physics | intermediate | 35 | [phys-03] | [Learn typical ε values for different operating modes Understand why QCW, DRSSTC, and burst modes have different ε Calibrate ε from experimental measurements Apply thermal accumulation effects to refine ε predictions] | [epsilon calibration QCW DRSSTC burst-mode thermal-accumulation] |
Empirical ε Values and Calibration
The energy per meter (ε) is not a universal constant - it depends strongly on the operating mode. Understanding typical values and calibration methods is essential for accurate spark growth modeling.
Typical ε Values by Operating Mode
QCW (Quasi-Continuous Wave)
ε ≈ 5-15 J/m
Characteristics:
- Long ramp times: 5-20 ms
- Channel stays hot throughout growth
- Efficient leader formation
- Minimal re-ionization needed
- Each joule efficiently extends length
Why low ε (efficient)?
- Continuous power maintains channel ionization
- Thermal ionization kept active
- Leaders form and persist
- Minimal energy wasted on re-starting
Typical coil parameters:
- Medium-high power: 10-100 kW
- Moderate duty cycle: 1-10%
- Linear voltage ramp
- Long sparks: 2-5+ m
Hybrid DRSSTC (Moderate Duty Cycle)
ε ≈ 20-40 J/m
Characteristics:
- Medium pulse lengths: 1-5 ms
- Mix of streamers and leaders
- Some thermal accumulation between pulses
- Moderate efficiency
Why moderate ε?
- Not quite continuous like QCW
- Some cooling between bursts
- Partial re-ionization required
- Both streamer and leader mechanisms active
Typical coil parameters:
- High power: 50-200 kW peak
- Moderate duty cycle: 5-15%
- Partial interrupter control
- Good balance: length and brightness
Burst Mode (Hard-Pulsed)
ε ≈ 30-100+ J/m
Characteristics:
- Short pulses: <500 μs typical
- Channel cools between pulses
- Mostly streamers, bright but short
- Must re-ionize repeatedly
- Poor length efficiency
Why high ε (inefficient)?
- Peak power → intense brightening and branching
- Channel cools between bursts (ms timescale)
- Energy dumped into light and heat, not length
- Must restart from cold each time
- High ionization overhead
Typical coil parameters:
- Very high peak power: 100-500+ kW
- Low duty cycle: 0.1-2%
- Bang energy: 10-100+ J per burst
- Short sparks: 0.5-2 m despite high energy
Single-Shot Impulse
ε ≈ 50-150+ J/m
Characteristics:
- One-time discharge (capacitor bank)
- No thermal memory from previous events
- All energy must come from single pulse
- Very high ε due to complete inefficiency
Why very high ε?
- Starting from completely cold air
- No accumulated ionization
- Transient streamer formation
- Most energy into flash and noise
Physical Explanation for ε Differences
QCW Efficiency (Low ε)
Energy flow:
1. Initial streamers form (t = 0)
2. Current flows → Joule heating (t = 0-1 ms)
3. Channel heats → thermal ionization (t = 1-2 ms)
4. Leader forms from base (t = 2-5 ms)
5. Leader maintained by continuous power (t = 5-20 ms)
6. New growth builds on existing hot ionization
7. Minimal wasted energy
Result: Each joule goes into extending the channel, not re-creating what already exists.
Burst Inefficiency (High ε)
Energy flow:
1. Pulse creates bright streamer (t = 0-100 μs)
2. Pulse ends, no more power (t = 100 μs)
3. Channel begins cooling (t = 0.1-1 ms)
4. Thermal diffusion and convection cool channel
5. Ionization recombines
6. Next pulse must re-ionize cold gas (t = 1-10 ms)
7. Energy wasted heating the same air repeatedly
Result: Energy into brightening and repeated ionization overhead, not cumulative length.
Analogy: Boiling Water
Low ε (QCW):
- Keep burner on continuously
- Maintain simmer (steady state)
- Efficient: minimal energy to maintain temperature
High ε (Burst):
- Pulse burner on/off repeatedly
- Water cools between pulses
- Inefficient: must reheat repeatedly
Calibration Procedure
To calibrate ε for your specific coil:
Step 1: Measure Delivered Energy
From SPICE simulation:
E_delivered = ∫ P_spark(t) dt
where P_spark = instantaneous power to spark
Integration from t = 0 to end of ramp
From measurements (if available):
E_delivered ≈ E_capacitor - E_losses
where E_capacitor = ½ C_primary V_primary²
E_losses = resistive, core, switching losses
Step 2: Measure Final Spark Length
Direct measurement:
- Photograph spark with scale reference
- Measure from topload to tip
- Average over multiple runs (sparks vary!)
- Use median or typical length, not maximum outlier
Typical measurement uncertainty:
- ±10-20% due to spark variability
- Branching makes "length" ambiguous
- Use main channel length
Step 3: Calculate ε
ε = E_delivered / L_final [J/m]
Example:
E_delivered = 45 J (from SPICE)
L_final = 1.8 m (measured)
ε = 45 J / 1.8 m = 25 J/m
Step 4: Verify and Refine
Repeat for different power levels:
- Change primary voltage or pulse width
- Measure new E_delivered and L_final
- Calculate ε for each run
- Average to get robust estimate
Check for consistency:
- ε should be approximately constant (±30%)
- Large variations indicate:
- Voltage-limited at some power levels
- Thermal accumulation effects
- Operating mode changes
Thermal Accumulation Effects
For more advanced modeling, ε can decrease during long ramps due to thermal accumulation:
ε(t) = ε₀ / (1 + α × ∫P_stream dt)
where:
ε₀ = initial energy per meter [J/m]
α = thermal accumulation factor [1/J]
∫P_stream dt = accumulated energy [J]
Physical meaning:
- As channel heats up, ionization becomes easier
- Less energy needed per meter as temperature rises
- ε decreases with accumulated heating
Typical values:
- ε₀ ≈ 15 J/m (initial, cold start)
- α ≈ 0.01-0.05 [1/J]
- After 50 J accumulated: ε ≈ 15/(1 + 0.03×50) = 6 J/m
When to use:
- Long QCW ramps (>10 ms)
- High accumulated energy (>30 J)
- For short bursts: ε ≈ ε₀ (constant)
Simplified model: Most practitioners use constant ε for simplicity:
- Choose ε representing average over ramp
- Simpler and usually adequate
- Advanced users can implement ε(t) in simulation
WORKED EXAMPLE: Calibration from Data
Given: Three experimental runs on a QCW coil:
| Run | V_primary | E_delivered | L_measured |
|---|---|---|---|
| 1 | 200 V | 25 J | 2.2 m |
| 2 | 250 V | 38 J | 3.1 m |
| 3 | 300 V | 55 J | 4.5 m |
Find: (a) Calculate ε for each run (b) Average ε for this coil (c) Assess consistency
Solution
Part (a): ε for each run
Run 1: ε₁ = E₁ / L₁ = 25 J / 2.2 m = 11.4 J/m
Run 2: ε₂ = E₂ / L₂ = 38 J / 3.1 m = 12.3 J/m
Run 3: ε₃ = E₃ / L₃ = 55 J / 4.5 m = 12.2 J/m
Part (b): Average ε
ε_avg = (ε₁ + ε₂ + ε₃) / 3
= (11.4 + 12.3 + 12.2) / 3
= 12.0 J/m
Recommended value: ε ≈ 12 J/m
Part (c): Consistency assessment
Standard deviation: σ ≈ 0.5 J/m
Coefficient of variation: CV = σ/μ = 0.5/12 = 4.2%
Excellent consistency! (<5% variation)
Interpretation:
- ε is nearly constant across power range
- Coil is NOT voltage-limited in this range
- Pure power-limited growth (field threshold always met)
- Can confidently use ε = 12 J/m for predictions
If we saw large variation:
Example: ε₁ = 10 J/m, ε₂ = 15 J/m, ε₃ = 30 J/m
This would indicate:
- Run 3 hitting voltage limit (inefficient growth)
- Possible mode transition (streamers vs leaders)
- Need to reassess model assumptions
WORKED EXAMPLE: Predicting Performance Change
Given:
- Current coil: Burst mode, ε = 65 J/m, E_bang = 80 J, L_typical = 1.2 m
- Proposed upgrade: Convert to QCW with ε = 12 J/m, same E_total = 80 J
Find: (a) Predicted length after QCW conversion (b) Percentage improvement (c) Required power for 10 ms ramp
Solution
Part (a): Predicted QCW length
L_QCW = E_total / ε_QCW
= 80 J / 12 J/m
= 6.67 m
Predicted length ≈ 6.7 m
Part (b): Improvement
Improvement = (L_QCW - L_burst) / L_burst × 100%
= (6.67 - 1.2) / 1.2 × 100%
= 456% increase in length!
Or: 6.67/1.2 = 5.6× longer sparks
Part (c): Required power
For 10 ms ramp:
P_avg = E_total / T_ramp
= 80 J / 0.010 s
= 8,000 W
= 8 kW average
Peak power higher (depends on waveform)
Typical: P_peak ≈ 1.5-2 × P_avg ≈ 12-16 kW
Reality check:
- 6.7 m prediction assumes NOT voltage-limited
- Actual length limited by topload voltage capability
- Still expect major improvement over burst mode
- Might achieve 3-4 m instead of 6.7 m (voltage limit)
Summary Table: ε by Operating Mode
| Mode | ε Range [J/m] | Characteristics | Best For |
|---|---|---|---|
| QCW | 5-15 | Efficient leaders, long ramps | Maximum length |
| DRSSTC Hybrid | 20-40 | Mixed streamers/leaders | Balanced length & brightness |
| Burst Mode | 30-100+ | Bright streamers, short pulses | Visual spectacle, music |
| Single-Shot | 50-150+ | One-time discharge | Impulse testing, demonstrations |
Choosing operating mode:
- Goal: Length → QCW (low ε)
- Goal: Brightness → Burst (high peak power)
- Goal: Music/modulation → Burst (rapid on/off)
- Goal: Efficiency → QCW (low ε, lower losses)
Key Takeaways
- QCW: ε ≈ 5-15 J/m - Most efficient, maintains hot channel
- Hybrid DRSSTC: ε ≈ 20-40 J/m - Moderate efficiency, mixed mechanisms
- Burst mode: ε ≈ 30-100+ J/m - Least efficient, repeated re-ionization
- Calibration: ε = E_delivered / L_measured from experimental runs
- Consistency check: ε should be approximately constant if power-limited
- Thermal accumulation: Advanced models use ε(t) decreasing with heating
- Operating mode choice: Trades off length efficiency vs brightness/aesthetics
Practice
{exercise:phys-ex-04}
Problem 1: A coil delivers 60 J in burst mode and produces 0.9 m sparks. Calculate ε. If converted to QCW with same energy, estimate new length assuming ε = 10 J/m.
Problem 2: Calibration runs give: ε₁ = 14 J/m (25 J delivered), ε₂ = 13 J/m (40 J), ε₃ = 28 J/m (90 J). What does the sudden increase in ε₃ suggest?
Problem 3: Explain why burst mode has higher ε than QCW despite delivering the same total energy. What happens to the "wasted" energy?
Next Lesson: Thermal Memory Effects