--- id: phys-04 title: "Empirical ε Values and Calibration" section: "Spark Growth Physics" difficulty: "intermediate" estimated_time: 35 prerequisites: ["phys-03"] objectives: - Learn typical ε values for different operating modes - Understand why QCW, DRSSTC, and burst modes have different ε - Calibrate ε from experimental measurements - Apply thermal accumulation effects to refine ε predictions tags: ["epsilon", "calibration", "QCW", "DRSSTC", "burst-mode", "thermal-accumulation"] --- # Empirical ε Values and Calibration The energy per meter (ε) is not a universal constant - it depends strongly on the operating mode. Understanding typical values and calibration methods is essential for accurate spark growth modeling. ## Typical ε Values by Operating Mode ### QCW (Quasi-Continuous Wave) **ε ≈ 5-15 J/m** **Characteristics:** - Long ramp times: 5-20 ms - Channel stays hot throughout growth - Efficient leader formation - Minimal re-ionization needed - Each joule efficiently extends length **Why low ε (efficient)?** - Continuous power maintains channel ionization - Thermal ionization kept active - Leaders form and persist - Minimal energy wasted on re-starting **Typical coil parameters:** - Medium-high power: 10-100 kW - Moderate duty cycle: 1-10% - Linear voltage ramp - Long sparks: 2-5+ m ### Hybrid DRSSTC (Moderate Duty Cycle) **ε ≈ 20-40 J/m** **Characteristics:** - Medium pulse lengths: 1-5 ms - Mix of streamers and leaders - Some thermal accumulation between pulses - Moderate efficiency **Why moderate ε?** - Not quite continuous like QCW - Some cooling between bursts - Partial re-ionization required - Both streamer and leader mechanisms active **Typical coil parameters:** - High power: 50-200 kW peak - Moderate duty cycle: 5-15% - Partial interrupter control - Good balance: length and brightness ### Burst Mode (Hard-Pulsed) **ε ≈ 30-100+ J/m** **Characteristics:** - Short pulses: <500 μs typical - Channel cools between pulses - Mostly streamers, bright but short - Must re-ionize repeatedly - Poor length efficiency **Why high ε (inefficient)?** - Peak power → intense brightening and branching - Channel cools between bursts (ms timescale) - Energy dumped into light and heat, not length - Must restart from cold each time - High ionization overhead **Typical coil parameters:** - Very high peak power: 100-500+ kW - Low duty cycle: 0.1-2% - Bang energy: 10-100+ J per burst - Short sparks: 0.5-2 m despite high energy ### Single-Shot Impulse **ε ≈ 50-150+ J/m** **Characteristics:** - One-time discharge (capacitor bank) - No thermal memory from previous events - All energy must come from single pulse - Very high ε due to complete inefficiency **Why very high ε?** - Starting from completely cold air - No accumulated ionization - Transient streamer formation - Most energy into flash and noise ## Physical Explanation for ε Differences ### QCW Efficiency (Low ε) **Energy flow:** ``` 1. Initial streamers form (t = 0) 2. Current flows → Joule heating (t = 0-1 ms) 3. Channel heats → thermal ionization (t = 1-2 ms) 4. Leader forms from base (t = 2-5 ms) 5. Leader maintained by continuous power (t = 5-20 ms) 6. New growth builds on existing hot ionization 7. Minimal wasted energy ``` **Result:** Each joule goes into extending the channel, not re-creating what already exists. ### Burst Inefficiency (High ε) **Energy flow:** ``` 1. Pulse creates bright streamer (t = 0-100 μs) 2. Pulse ends, no more power (t = 100 μs) 3. Channel begins cooling (t = 0.1-1 ms) 4. Thermal diffusion and convection cool channel 5. Ionization recombines 6. Next pulse must re-ionize cold gas (t = 1-10 ms) 7. Energy wasted heating the same air repeatedly ``` **Result:** Energy into brightening and repeated ionization overhead, not cumulative length. ### Analogy: Boiling Water **Low ε (QCW):** - Keep burner on continuously - Maintain simmer (steady state) - Efficient: minimal energy to maintain temperature **High ε (Burst):** - Pulse burner on/off repeatedly - Water cools between pulses - Inefficient: must reheat repeatedly ## Calibration Procedure To calibrate ε for your specific coil: ### Step 1: Measure Delivered Energy **From SPICE simulation:** ``` E_delivered = ∫ P_spark(t) dt where P_spark = instantaneous power to spark Integration from t = 0 to end of ramp ``` **From measurements (if available):** ``` E_delivered ≈ E_capacitor - E_losses where E_capacitor = ½ C_primary V_primary² E_losses = resistive, core, switching losses ``` ### Step 2: Measure Final Spark Length **Direct measurement:** - Photograph spark with scale reference - Measure from topload to tip - Average over multiple runs (sparks vary!) - Use median or typical length, not maximum outlier **Typical measurement uncertainty:** - ±10-20% due to spark variability - Branching makes "length" ambiguous - Use main channel length ### Step 3: Calculate ε ``` ε = E_delivered / L_final [J/m] Example: E_delivered = 45 J (from SPICE) L_final = 1.8 m (measured) ε = 45 J / 1.8 m = 25 J/m ``` ### Step 4: Verify and Refine **Repeat for different power levels:** - Change primary voltage or pulse width - Measure new E_delivered and L_final - Calculate ε for each run - Average to get robust estimate **Check for consistency:** - ε should be approximately constant (±30%) - Large variations indicate: - Voltage-limited at some power levels - Thermal accumulation effects - Operating mode changes ## Thermal Accumulation Effects For more advanced modeling, ε can decrease during long ramps due to thermal accumulation: ``` ε(t) = ε₀ / (1 + α × ∫P_stream dt) where: ε₀ = initial energy per meter [J/m] α = thermal accumulation factor [1/J] ∫P_stream dt = accumulated energy [J] ``` **Physical meaning:** - As channel heats up, ionization becomes easier - Less energy needed per meter as temperature rises - ε decreases with accumulated heating **Typical values:** - ε₀ ≈ 15 J/m (initial, cold start) - α ≈ 0.01-0.05 [1/J] - After 50 J accumulated: ε ≈ 15/(1 + 0.03×50) = 6 J/m **When to use:** - Long QCW ramps (>10 ms) - High accumulated energy (>30 J) - For short bursts: ε ≈ ε₀ (constant) **Simplified model:** Most practitioners use constant ε for simplicity: - Choose ε representing average over ramp - Simpler and usually adequate - Advanced users can implement ε(t) in simulation --- ## WORKED EXAMPLE: Calibration from Data **Given:** Three experimental runs on a QCW coil: | Run | V_primary | E_delivered | L_measured | |-----|-----------|-------------|------------| | 1 | 200 V | 25 J | 2.2 m | | 2 | 250 V | 38 J | 3.1 m | | 3 | 300 V | 55 J | 4.5 m | **Find:** (a) Calculate ε for each run (b) Average ε for this coil (c) Assess consistency ### Solution **Part (a): ε for each run** ``` Run 1: ε₁ = E₁ / L₁ = 25 J / 2.2 m = 11.4 J/m Run 2: ε₂ = E₂ / L₂ = 38 J / 3.1 m = 12.3 J/m Run 3: ε₃ = E₃ / L₃ = 55 J / 4.5 m = 12.2 J/m ``` **Part (b): Average ε** ``` ε_avg = (ε₁ + ε₂ + ε₃) / 3 = (11.4 + 12.3 + 12.2) / 3 = 12.0 J/m Recommended value: ε ≈ 12 J/m ``` **Part (c): Consistency assessment** ``` Standard deviation: σ ≈ 0.5 J/m Coefficient of variation: CV = σ/μ = 0.5/12 = 4.2% Excellent consistency! (<5% variation) ``` **Interpretation:** - ε is nearly constant across power range - Coil is NOT voltage-limited in this range - Pure power-limited growth (field threshold always met) - Can confidently use ε = 12 J/m for predictions **If we saw large variation:** ``` Example: ε₁ = 10 J/m, ε₂ = 15 J/m, ε₃ = 30 J/m This would indicate: - Run 3 hitting voltage limit (inefficient growth) - Possible mode transition (streamers vs leaders) - Need to reassess model assumptions ``` --- ## WORKED EXAMPLE: Predicting Performance Change **Given:** - Current coil: Burst mode, ε = 65 J/m, E_bang = 80 J, L_typical = 1.2 m - Proposed upgrade: Convert to QCW with ε = 12 J/m, same E_total = 80 J **Find:** (a) Predicted length after QCW conversion (b) Percentage improvement (c) Required power for 10 ms ramp ### Solution **Part (a): Predicted QCW length** ``` L_QCW = E_total / ε_QCW = 80 J / 12 J/m = 6.67 m Predicted length ≈ 6.7 m ``` **Part (b): Improvement** ``` Improvement = (L_QCW - L_burst) / L_burst × 100% = (6.67 - 1.2) / 1.2 × 100% = 456% increase in length! Or: 6.67/1.2 = 5.6× longer sparks ``` **Part (c): Required power** ``` For 10 ms ramp: P_avg = E_total / T_ramp = 80 J / 0.010 s = 8,000 W = 8 kW average Peak power higher (depends on waveform) Typical: P_peak ≈ 1.5-2 × P_avg ≈ 12-16 kW ``` **Reality check:** - 6.7 m prediction assumes NOT voltage-limited - Actual length limited by topload voltage capability - Still expect major improvement over burst mode - Might achieve 3-4 m instead of 6.7 m (voltage limit) --- ## Summary Table: ε by Operating Mode | Mode | ε Range [J/m] | Characteristics | Best For | |------|---------------|-----------------|----------| | **QCW** | 5-15 | Efficient leaders, long ramps | Maximum length | | **DRSSTC Hybrid** | 20-40 | Mixed streamers/leaders | Balanced length & brightness | | **Burst Mode** | 30-100+ | Bright streamers, short pulses | Visual spectacle, music | | **Single-Shot** | 50-150+ | One-time discharge | Impulse testing, demonstrations | **Choosing operating mode:** - **Goal: Length** → QCW (low ε) - **Goal: Brightness** → Burst (high peak power) - **Goal: Music/modulation** → Burst (rapid on/off) - **Goal: Efficiency** → QCW (low ε, lower losses) --- ## Key Takeaways - **QCW: ε ≈ 5-15 J/m** - Most efficient, maintains hot channel - **Hybrid DRSSTC: ε ≈ 20-40 J/m** - Moderate efficiency, mixed mechanisms - **Burst mode: ε ≈ 30-100+ J/m** - Least efficient, repeated re-ionization - **Calibration**: ε = E_delivered / L_measured from experimental runs - **Consistency check**: ε should be approximately constant if power-limited - **Thermal accumulation**: Advanced models use ε(t) decreasing with heating - **Operating mode choice**: Trades off length efficiency vs brightness/aesthetics ## Practice {exercise:phys-ex-04} **Problem 1:** A coil delivers 60 J in burst mode and produces 0.9 m sparks. Calculate ε. If converted to QCW with same energy, estimate new length assuming ε = 10 J/m. **Problem 2:** Calibration runs give: ε₁ = 14 J/m (25 J delivered), ε₂ = 13 J/m (40 J), ε₃ = 28 J/m (90 J). What does the sudden increase in ε₃ suggest? **Problem 3:** Explain why burst mode has higher ε than QCW despite delivering the same total energy. What happens to the "wasted" energy? --- **Next Lesson:** [Thermal Memory Effects](05-thermal-memory.md)