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id: phys-ex-01a
type: calculation
difficulty: easy
points: 10
related_lesson: phys-01
question: |
A 0.8 m spark has V_top = 280 kV and tip enhancement factor κ = 4.
(a) Calculate E_tip
(b) If E_propagation = 0.5 MV/m, can the spark grow further?
hints:
- "E_average = V_top / L"
- "E_tip = κ × E_average"
- "Growth continues when E_tip > E_propagation"
solution:
steps:
- "Part (a): Calculate average field"
- "E_average = V_top / L = 280×10³ V / 0.8 m = 350 kV/m = 0.35 MV/m"
- "Calculate tip field"
- "E_tip = κ × E_average = 4 × 0.35 = 1.4 MV/m"
- "Part (b): Compare to threshold"
- "E_tip = 1.4 MV/m"
- "E_propagation = 0.5 MV/m"
- "E_tip > E_propagation ✓"
- "Yes, spark can grow further"
- "Safety margin: 1.4 / 0.5 = 2.8× above threshold"
answer_a: "1.4"
unit_a: "MV/m"
answer_b: "yes"
margin: "2.8"
tolerance: 5.0
explanation: |
The tip field (1.4 MV/m) significantly exceeds the propagation threshold
(0.5 MV/m), with a comfortable 2.8× safety margin. This spark is not voltage-
limited and can continue growing. The enhancement factor κ = 4 concentrates the
average field (0.35 MV/m) at the tip, creating sufficient field strength for
sustained ionization and growth. If this spark has adequate power, it can extend
well beyond 0.8 m.
related_concepts: ["electric-field", "tip-enhancement", "growth-criterion", "voltage-limited"]